#include <stdio.h>
#include <stdlib.h>
#define macro(n) for(k=0;k<n;k++)sum+=1/(float)(k+1)
int main(void)
{
int k,n;
float sum = 0.0f;
printf("計算1/1+1/2+1/3+‧‧‧+1/n的輸出結果為\n"); macro(n);
return 0;
}
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